The second difference of this quadratic pattern is 2.
The first term of this quadratic pattern is 10.
A sequence of numbers has a quadratic pattern when its sequence of second differences is constant. Therefore,
let the first and fourth term be a and b.
Therefore,
first difference:
1 - a; - 6 - 1 = -7; b + 6; -14 - b;
Second difference:
The second difference is constant . Therefore,
-7 - (1 - a) = -8 + a; b + 6 + 7 = b + 13; -14 - b - b - 6 = -2b - 20;
Therefore,
b + 13 = -8 + a
b - a = -21
Then,
-2b - 20 = b + 13
-3b = 33
b = 33 / -3
b = - 11
Therefore,
- 11 - a = - 21
-a = -21 + 11
-a = -10
a = 10
Hence, the second difference = b + 13 = -11 + 13 = 2
First term = a
Therefore,
a = 10
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