Given:
Consider the below figure attaches with this question.
To find:
The size of angle x.
Solution:
Law of Cosines:
[tex]\cos A=\dfrac{b^2+c^2-a^2}{2bc}[/tex]
Three sides of the triangle are 11 cm, 8 cm, 15 cm. Since 11 cm is the opposite side of the angle x, therefore [tex]a=11[/tex].
Let [tex]A=x,a=11,b=8,c=15[/tex]. Substitute these values in the above formula.
[tex]\cos x=\dfrac{8^2+15^2-11^2}{2(8)(15)}[/tex]
[tex]\cos x=\dfrac{64+225-121}{240}[/tex]
[tex]\cos x=\dfrac{168}{240}[/tex]
[tex]\cos x=0.7[/tex]
Taking cos inverse on both sides, we get
[tex]x=\cos^{-1} 0.7[/tex]
[tex]x=45.572996^\circ[/tex]
[tex]x\approx 45.6^\circ[/tex]
Therefore, the measure of angle x is 45.6°.