Answer:
[tex] l = \sqrt{261}\: in[/tex]
Step-by-step explanation:
Height of the cone h = 15 in
Radius of the cone r = 12/2 = 6 in
We need to find slant height (l) =?
[tex] \because l = \sqrt{ {r}^{2} + {h}^{2} } \\ \\ \therefore l = \sqrt{ {6}^{2} + {15}^{2} } \\ \\\therefore l = \sqrt{36 + 225} \\ \\\therefore l = \sqrt{261} \\ [/tex]
