Answer:
[tex]x=49.16^{\circ}[/tex]
Step-by-step explanation:
We need to find the value of x in the given figure.
It is a right angled triangle, in which base is 19, height is 22.
We can use trigonometry to find x.
We know that,
[tex]\tan\theta=\dfrac{P}{B}[/tex]
Where
P is perpendicular and B is base
So,
[tex]\tan x=\dfrac{22}{19}\\\\x=\tan^{-1}(1.157)\\\\x=49.16^{\circ}[/tex]
So, the value of x is equal to [tex]49.16^{\circ}[/tex].
