Charlotte walks home from school every day at a rate of
4 miles per hour. It takes her 30-minutes to reach
home. Her brother, Noah, runs home from the same
school every day at a rate of 6 miles per hour. How
many fewer minutes does it take Noah than Charlotte
to reach home from school each day? Be sure to
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Answer:

It takes 10 fewer minutes for Noah than for Charlotte to home from school each day.

Step-by-step explanation:

We use the following relation to solve this question:

[tex]v = \frac{d}{t}[/tex]

In which v is the velocity, d is the distance, and t is the time.

Finding the distance:

Charlotte walks home from school every day at a rate of 4 miles per hour. It takes her 30-minutes to reach home.

This means that [tex]t = 0.5, v = 4[/tex]. Time is 0.5 because as the velocity is in miles per hour, the time has to be in hours. We use this to find d.

[tex]v = \frac{d}{t}[/tex]

[tex]4 = \frac{d}{0.5}[/tex]

[tex]d = 4*0.5 = 2[/tex]

The distance is of 2 miles.

Her brother, Noah, runs home from the same school every day at a rate of 6 miles per hour.

We have to find t, in hours, for which [tex]v = 6, d = 2[/tex]. So

[tex]v = \frac{d}{t}[/tex]

[tex]6 = \frac{2}{t}[/tex]

[tex]6t = 2[/tex]

[tex]t = \frac{1}{3}[/tex]

A third of an hour. In minutes, this is a third of 60, that is 60/3 = 20 minutes.

How many fewer minutes does it take Noah than Charlotte to reach home from school each day?

Noah: 20 minutes

Charlotte: 30 minutes

30 - 20 = 10

It takes 10 fewer minutes for Noah than for Charlotte to home from school each day.

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