Answer:
It takes 10 fewer minutes for Noah than for Charlotte to home from school each day.
Step-by-step explanation:
We use the following relation to solve this question:
[tex]v = \frac{d}{t}[/tex]
In which v is the velocity, d is the distance, and t is the time.
Finding the distance:
Charlotte walks home from school every day at a rate of 4 miles per hour. It takes her 30-minutes to reach home.
This means that [tex]t = 0.5, v = 4[/tex]. Time is 0.5 because as the velocity is in miles per hour, the time has to be in hours. We use this to find d.
[tex]v = \frac{d}{t}[/tex]
[tex]4 = \frac{d}{0.5}[/tex]
[tex]d = 4*0.5 = 2[/tex]
The distance is of 2 miles.
Her brother, Noah, runs home from the same school every day at a rate of 6 miles per hour.
We have to find t, in hours, for which [tex]v = 6, d = 2[/tex]. So
[tex]v = \frac{d}{t}[/tex]
[tex]6 = \frac{2}{t}[/tex]
[tex]6t = 2[/tex]
[tex]t = \frac{1}{3}[/tex]
A third of an hour. In minutes, this is a third of 60, that is 60/3 = 20 minutes.
How many fewer minutes does it take Noah than Charlotte to reach home from school each day?
Noah: 20 minutes
Charlotte: 30 minutes
30 - 20 = 10
It takes 10 fewer minutes for Noah than for Charlotte to home from school each day.