Answer:
[tex]P(Sum = 9) = \frac{1}{9}[/tex]
Step-by-step explanation:
Given
Outcomes of rolling two dice
Required
P(Sum = 9)
From the given outcomes, we have:
[tex]n(S) = 36[/tex] -- the sample size
[tex]Sum = 9:=\{(3,6),(4,5),(5,4),(6,3)\}[/tex]
So.
[tex]n(Sum = 9) = 4[/tex]
The probability is:
[tex]P(Sum = 9) = \frac{n(Sum = 9)}{n(S)}[/tex]
[tex]P(Sum = 9) = \frac{4}{36}[/tex]
Simplify
[tex]P(Sum = 9) = \frac{1}{9}[/tex]
