Question

The functions r and s are defined as follows.
r(x) =- 2x+2
s(x)=x²-2
Find the value of r(s (-2)).
r(s(-2)) = 1
口口
Х
?:

Answer 1

Answer:

r(s(-2)) = -2

Step-by-step explanation:

We are given these following functions:

$r(x) = -2x + 2$

$s(x) = x^2 - 2$

Find the value of r(s (-2)).

First we find the composition of r and s functions. It is:

$r(s(x)) = r(x^2-2) = -2(x^2-2) + 2 = -2x^2 + 6$

At x = -2

$r(s(-2)) = -2(-2)^2 + 6 = -8 + 6 = -2$

r(s(-2)) = -2