Question

What is the molarity of a solution which contains 58.5 g of sodium chloride dissolved in 0.500 l of solution?

Answer 1

The units of molarity are moles/liter, so you want to find the number of moles in one liter of a substance.
The molar mass of Sodium Chloride (NaCl) is approximately 58.5, gotten from the sum of the molar masses of sodium and chlorine
Molar Mass sodium = 23.0 grams/mole
Molar Mass chlorine = 35.5 grams/mole
Molar mass sodium chloride = 23.0 g/mol + 35.5 g/mol = 58.5 g/mol
Convert 58.5 grams to moles: (58.5 grams)/(58.5 grams/mol)
Leaves 1.00 moles of NaCl
Divide that by the number of liters of solution (0.500 liters)
(1.00moles)/(0.500 liters) = 2.00 moles/liter is your molarity

Answer 2

The molarity of the solution is "2.00 M".

Given values,

Mass of NaCl,

• 58.5 g

Molar mass of NaCl,

• 58.5 g/mol

Volume of solution,

• 0.5 L

→ The molarity of the solution will be:

$M = \frac{Mass}{Molar \ mass}\times \frac{1}{V}$

    $= \frac{58.5}{58.5 }\times \frac{1}{0.5 }$

    $= \frac{1}{0.5}$

    $= 2.00 \ mole/L$

or,

    $= 2.00 \ M$

Thus the response above is correct.

Learn more:

https://brainly.com/question/14753222