Answer:
[tex] y = 1 [/tex]
Step-by-step explanation:
Given:
[tex] a^{3y - 5} = \frac{1}{a^2} [/tex]
Apply the negative exponent rule
[tex] a^{3y - 5} = a^{-2} [/tex]
The bases will cancel each other
[tex] 3y - 5 = -2 [/tex]
[tex] 3y - 5 + 5 = -2 + 5 [/tex]
[tex] 3y = 3 [/tex]
[tex] \frac{3y}{3} = \frac{3}{3} [/tex]
[tex] y = 1 [/tex]
