Question

In ΔHIJ, the measure of ∠J=90°, the measure of ∠H=8°, and HI = 30 feet. Find the length of IJ to the nearest tenth of a foot.

Answer 1

Answer: 4.2

Step-by-step explanation:

Sin(H)=x/30 then cross multiply

30sin(8)=x

X=4.1752... but rounded it’s 4.2

Answer 2

Answer:

It's 4.2

Step-by-step explanation: