Answer:
The surface area of the given pyramid is 112 [tex]inches^{2}[/tex].
Step-by-step explanation:
Base length of the pyramid = 4 inches
Area of the base = [tex]length^{2}[/tex]
= [tex]4^{2}[/tex]
= 16
Area of its base = 16 [tex]inches^{2}[/tex]
Area of one of its triangular surface = [tex]\frac{1}{2}[/tex] x base x height
= [tex]\frac{1}{2}[/tex] x 4 x 12
= 2 x 12
= 24 [tex]inches^{2}[/tex]
Area of all its four triangular surfaces = 4 x 24
= 96 [tex]inches^{2}[/tex]
surface area of the pyramid = sum of areas of all its surfaces
= 16 + 96
= 112 [tex]inches^{2}[/tex]
The surface area of the given pyramid is 112 [tex]inches^{2}[/tex].
