Question

What is the net ionic equation for the reaction that occurs when aqueous solutions of koh and hno3 are mixed?

Answer 1

This is a neutralisation reaction, so we know that the products formed are salt and water.

First, we balance the chemical equation:

KOH + HNO3 ----> KNO3 + H2O.

After that, we split the compounds into their respective charges.

K+ + OH- + H+ + NO3- ----------> K+ + NO3- + H2O*

(*note that liquid cannpt be splitted.)

After that we reduce the chemical equation by removing the common ones.

OH- + H+ --------> H2O

Tada.

Answer 2

The net ionic equation for aqueous solution of KOH and $\rm HNO_3$ has been $\rm H^+\;(aq)\;+OH^-\;(aq)\;\rightarrow\;H_2O\;(l)$.

The ionic equation has been the representation of the ionic form of products and reactants in the solution. The reaction of potassium hydroxide with Nitric acid results in the formation of salt and water.

The chemical equation for the reaction has been:

$\rm KOH\;(aq)\;+\;HNO_3\;(aq)\;\rightarrow\;KNO_3\;(aq)\;+\;H_2O\;(l)$

The ionic equation for the reaction has been:

$\rm K^+\;(aq)\;+\;OH^-\;(aq)\;+\;H^+\;(aq)\;+\;NO_3^-\;(aq)\;\rightarrow\;K^+\;(aq)\;+\;NO_3^-\;(aq)\;+\;H_2O\;(l)$

The net ionic equation has eliminated ions, that has been present on both product and reactant side of the reaction.

The elimination will results in the net ionic equation as:

$\rm H^+\;(aq)\;+OH^-\;(aq)\;\rightarrow\;H_2O\;(l)$

For more information about the net ionic equation, refer to the link:

https://brainly.com/question/22885959