Answer:
[tex]x=\frac{b-ac}{a+2} ; a\neq -2[/tex]
Step-by-step explanation:
Multiply both sides: by x+c
a(x+c)=[tex]\frac{b-2x}{x+c}[/tex] (x+c)
Simplify: a(x+c)=b-2x
Expand: ax+ac=b-2x
Subtract ac from both sides: ax+ac-ac=b-2x-ac
Simplify: ax=b-2x-ac
Add 2x to both sides: ax+2x=b-2x-ac+2x
Simplify: ax+2x=b-ac
Factor ax+2x: x(a+2)
x(a+2)=b-ac
Divide both sides by a+2: [tex]\frac{x(a+2)}{a+2}[/tex] = [tex]\frac{b}{a+2}[/tex] - [tex]\frac{ac}{a+2}[/tex] ; a≠-2
Simplify: [tex]x=\frac{b-ac}{a+2} ; a\neq -2[/tex]