Answer:
The probability that Leon strikes is greater than Carlton strike is 0.40905
Step-by-step explanation:
From the question, we have;
The percentage of Carlton's rolls are strikes, [tex]\hat p_1[/tex] = 70%
The number of games Carlton played, n₁ = 25
The percentage of Leon's rolls that are strikes, [tex]\hat p_2[/tex] = 67%
The number of games Leon played, n₂ = 25
Therefore, we have;
[tex]\hat p=\dfrac{k_1 + k_2}{n_1 + n_2}[/tex]
Where;
k₁ = 0.7 × 25 = 17.5
k₂ = 0.67 × 25 = 16.75
[tex]\therefore \hat p=\dfrac{17.5 + 16.75}{25 + 25} = 0.685[/tex]
The test statistic is given as follows;
[tex]Z=\dfrac{\hat{p}_1-\hat{p}_2}{\sqrt{\hat{p} \cdot (1-\hat{p})\cdot \left (\dfrac{1}{n_{1}}+\dfrac{1}{n_{2}} \right )}}[/tex]
[tex]Z=\dfrac{0.7-0.67}{\sqrt{0.685 \cdot (1-0.685)\cdot \left (\dfrac{1}{25}+\dfrac{1}{25} \right )}} \approx 0.2283[/tex]
From the z-table, we have;
The p-value for Carlton strikes is greater than Leon's strike = 0.59095
∴ The p-value for Leon strikes is greater than Carlton strike = 1 - 0.59095 = 0.40905
The probability that Leon strikes is greater than Carlton strike = 0.40905