Question

How much resistance is required to limit the current from a 12 V battery to 3.6 mA?

Answer 1

Answer:

3333.3 ohm

Explanation:

V=IR so R =V/I (in Ampere) so convert 3.6 mA to 3.6*10^-3 A

so R =12/3.6*10^-3 =3333.3