Question

plz besties can you help me
a) show that k lies between - 8 and 1 in the following inequality
${k}^{2} + 7k \leqslant 8$
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Answer 1

Answer:

-8≤k≤1

Step-by-step explanation:

k²+7k-8≤0

(k+8)x(k-1)≤0

k1= -8

k2= 1

-8≤k≤1