Given:
Length of the rectangle = [tex]x+4[/tex]
Width of the rectangle = [tex]x[/tex]
The perimeter of the rectangle is less than 140.
To find:
The inequality for the given situation and solve it.
Solution:
We have,
[tex]l=x+4[/tex]
[tex]w=x[/tex]
We know that, the perimeter of a rectangle is
[tex]P=2(l+w)[/tex]
[tex]P=2(x+4+x)[/tex]
[tex]P=2(2x+4)[/tex]
[tex]P=4x+8[/tex]
It is given that the perimeter of the rectangle is less than 140.
[tex]P<140[/tex]
[tex]4x+8<140[/tex]
[tex]4x<140-8[/tex]
[tex]4x<132[/tex]
Divide both sides by 4.
[tex]x<\dfrac{132}{4}[/tex]
[tex]x<33[/tex]
Therefore, the correct option is A because the sign of inequality is < and the solution of inequality is [tex]x<33[/tex].