Question

What is an
equation of the line that passes through the points (-4,-4) and (4, 6)?

Answer 1

Answer:

Step-by-step explanation:

1.) Find the slope

$\frac{y_2-y_1}{x_2-x_1} = \frac{6-(-4)}{4-(-4)}= \frac{6+4}{4+4} = \frac{10}{8}=\frac{5}4}$ = m

2.) Use the  slope-point form for a line

$y-y_0=m(x-x_0)$

Pick any point (-4,-4) or (4,6) into $y_0 and x_0$

but your equation is y= 5/4x+1