Question

find the limit. lim (x-5)/((x^2)-25) x-> 5+

Answer 1

$\lim_{x \to 5} \frac{x-5}{ x^{2} -25} =( \frac{0}{0} ) = \\ =\lim_{x \to 5} \frac{x-5}{(x-5)(x+5)}= \\ =\lim_{x \to 5} \frac{1}{x+5}= \\ = \frac{1}{5+5}= \frac{1}{10}$ = 0.1