Question

at 12 noon, leslie recorded the temperature as 56 degrees f. The temperature had increased by 8 degrees f from 10am. The temperature at 8am was 2 degrees f warmer than it was at 10am. What was the temperature @ 8am. Please explain step by step. Thanks
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Answer 1

Let the temperature at 10am be x, then
x + 8 = 56
x = 56 - 8 = 48 degrees F

Let y be the temperature at 8am, then
y - 2 = 48
y = 48 + 2 = 50 degrees.

Answer 2

Ok so start with your 12:00 temperature: 56° F. You know that the 10:00 temp. was 8 degrees less than 56so:56°-8°=48°your 10:00 temp.=48°Now you know that the 8:00 temp was 2° warmer than your 10:00 temp. which was 48°simply: 48+2=50°your 8:00 temp. was 50°