Question

A flashlight has 6 batteries, 2 of which are defective. If 2 are selected at random without replacement, find the probability that both are defective.

Answer 1

2/6 x 1/5 = 2/30 = 1/15

Answer 2

The probability that both batteries are defective is 1/15

How to determine the probability?

The distribution of the batteries is given as:

Total = 6

Defective =2

The probability of selecting a battery is defective is:

P(Defective) = 2/6

Now, there are 5 batteries and 1 defective battery

The probability of selecting a battery is defective is:

P(Defective) = 1/5

The required probability is:

P = 2/6 * 1/5

Evaluate

P = 1/15

Hence, the probability that both are defective is 1/15

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