Respuesta :
16/4 = 4
3 * 2^4 = 3 * 16 = 48mg --
initial mass 8 weeks after the start = 8*7 = 56 56/4 = 14 48*(0.5)^14 ~ 0,002929688
initial mass 8 weeks after the start = 8*7 = 56 56/4 = 14 48*(0.5)^14 ~ 0,002929688
Answer:
1. 48 mg.
2. 12 mg.
Step-by-step explanation:
We have been given that the half-life of Palladium-100 is 4 days. After 16 days a sample of Palladium-100 has been reduced to a mass of 3 mg.
Half-life formula: [tex]A=a\cdot(\frac{1}{2})^{\frac{t}{h}}[/tex], where,
A = Final amount,
a = Initial amount,
t = Time,
h = Half-life.
Substitute the given values:
[tex]3=a\cdot(\frac{1}{2})^{\frac{16}{4}}[/tex]
[tex]3=a\cdot(0.5)^{4}[/tex]
[tex]3=a\cdot0.0625[/tex]
[tex]\frac{3}{0.0625}=\frac{3a\cdot0.0625}{0.0625}[/tex]
[tex]48=a[/tex]
Therefore, the initial mass of the sample was 48 mg.
To find the mass of sample after 8 weeks, we will substitute [tex]t=8[/tex] in half life formula.
[tex]A=48\cdot(\frac{1}{2})^{\frac{8}{4}}[/tex]
[tex]A=48\cdot(0.5)^{2}[/tex]
[tex]A=48\cdot 0.25[/tex]
[tex]A=12[/tex]
Therefore, the mass of sample after 8 weeks would be 12 mg.