Question

Yooo someone
The height of the isosceles trapezoid ABCD from the vertex D of the obtuse angle divides the longer base into sections AE and EB of 3 cm and 13 cm respectively. The triangle AED is isosceles. Calculate the area of the trapezoid ABCD.

Answer 1

Answer:

39 sq cm

Step-by-step explanation:

Ok.  Since ΔAED is isosceles, then the height of the trapezoid is 3 cm

One base is 16 and the other base is 16 - 3 - 3 = 10.

A = 1/2 h($b_{1}$ + $b_{2}$)  where $b_{1}$ and $b_{2}$ are lengths of the bases

A = 1/2(3)(10 + 16)

  = 1/2(3)(26)

  = 39 sq cm