I am the number '9'
To prove:
On multiplying 9 with different numbers, the sum of the digits of its product is always 9. Let's see;
9 × [tex]2 = 18[/tex]
where [tex](1 + 8 = 9)[/tex]
Now, multiplying it by 3
9 × 3 = 27
where [tex](2 + 7 = 9)[/tex]
Similarly,
9 × [tex]4 = 36[/tex]
where [tex](3 + 6 = 9)[/tex]
9 × [tex]5 = 45[/tex]
where [tex](4 + 5 = 9)[/tex]
9 × [tex]6 = 54[/tex]
where [tex](5 + 4 = 9)[/tex]
9 × [tex]7 = 63[/tex]
where [tex](6 + 3 = 9)[/tex]
Thus, option b i.e. 9 is the correct answer.
Learn more about 'numbers' here:
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