Question

Solve the following algebraic expressions
1) n(n-4) -n(5-n)
2)

Answer 1

Answer:

$n {}^{2} - 4n - 5n + n { }^{2} \\ = 2n {}^{2} - 9$

Hope it helps

Answer 2

Answer:

$\huge\boxed{1) 2n^2-9n}$

$\huge\boxed{2) 6c\³ + 4c\²}$

Step-by-step explanation:

Part 1:

= n(n-4)-n(5-n)

By distributive property

= n² - 4n - 5n + n²

= 2n² - 4n - 5n

= 2n² - 9n

Part 2:

= 4c(3c-c²)-2c²(4-5c)

Distributing brackets

= 12c² - 4c³ - 8c² + 10c³

Combining like terms

= 12c² - 8c² - 4c³ + 10c³

= 4c² + 6c³

= 6c³ + 4c²

$\rule[225]{225}{2}$

Hope this helped!

~AH1807