Answer:
The amount of steel used = 94.38 [tex]m^{2}[/tex]
Step-by-step explanation:
Height of the tank = 4.5 m.
Diameter of the tank = 4.2 m.
But,
radius = [tex]\frac{diameter}{2}[/tex]
= [tex]\frac{4.2}{2}[/tex]
radius = 2.1 m
Total surface area of a cylinder = 2[tex]\pi[/tex]rh + 2[tex]\pi[/tex][tex]r^{2}[/tex]
= 2[tex]\pi[/tex]r(r + h)
= 2 x [tex]\frac{22}{7}[/tex] x 2.1 (2.1 + 4.5)
= 44 x 0.3 (6.6)
= 87.12
Total surface area of a cylinder = 87.12 [tex]m^{2}[/tex]
Since [tex]\frac{1}{12}[/tex] of the steel was wasted, then;
[tex]\frac{1}{12}[/tex] x 87.12 = 7.26 [tex]m^{2}[/tex]
Actual area of steel sheet used = 87.12 + 7.26
= 94.38 [tex]m^{2}[/tex]
Thus, 94.38 [tex]m^{2}[/tex] of steel was used in making the tank.