Respuesta :
Answer:
[tex]500(.75)^{n}[/tex]
Step-by-step explanation:
It is changing exponentially because if you are eating a fraction of the left over m & m's, that is a different amount each time so it can't be linear.
500(1-(1/4))^n
[tex]500(.75)^{n}[/tex]
Initial quantity of the candies = 500
If we eat [tex]\frac{1}{4}[/tex] candies each day, number of candies after one day
= 500 - [tex]\frac{1}{4}\times 500[/tex]
= 500 - 125
= 375
Number of candies after two days
= 375 - [tex]\frac{1}{4}\times (375)[/tex]
= 281.25
Therefore, sequence formed will be.
500, 375, 281.25.......n days
Ratio of 2nd and 1st term = [tex]\frac{375}{500}[/tex] = 0.75
Ratio of 3rd and 2nd term = [tex]\frac{281.75}{375}[/tex] = 0.75
Therefore, there is a common ratio of 0.75 in each successive and previous term.
And the sequence will be a geometric sequence.
Expression for the exponential decay is,
[tex]A=A_0(1-r)^n[/tex]
Here, A = Final amount
[tex]A_0=[/tex] Initial amount
r = percentage decrease
n = duration
From the given question,
[tex]A_0=500[/tex]
r = [tex]\frac{1}{4}=\frac{25}{100}[/tex]
Therefore, equation for the decrease in number of candies will be.
[tex]A=500(1-0.25)^n[/tex]
[tex]A=500(0.75)^n[/tex]
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