Suppose that you have a bowl of 500 m&m candies, and each day you eat 1/4 of the candies you have. Is the number of candies left changing linearly or exponentially? Write an equation to model the number of candies left after n days.

Respuesta :

Answer:

[tex]500(.75)^{n}[/tex]

Step-by-step explanation:

It is changing exponentially because if you are eating a fraction of the left over m & m's, that is a different amount each time so it can't be linear.

500(1-(1/4))^n

[tex]500(.75)^{n}[/tex]

Initial quantity of the candies = 500

If we eat [tex]\frac{1}{4}[/tex] candies each day, number of candies after one day

= 500 - [tex]\frac{1}{4}\times 500[/tex]

= 500 - 125

= 375

Number of candies after two days

= 375 - [tex]\frac{1}{4}\times (375)[/tex]

= 281.25

Therefore, sequence formed will be.

500, 375, 281.25.......n days

Ratio of 2nd and 1st term = [tex]\frac{375}{500}[/tex] = 0.75

Ratio of 3rd and 2nd term = [tex]\frac{281.75}{375}[/tex] = 0.75

Therefore, there is a common ratio of 0.75 in each successive and previous term.

And the sequence will be a geometric sequence.

Expression for the exponential decay is,

[tex]A=A_0(1-r)^n[/tex]

Here, A = Final amount

[tex]A_0=[/tex] Initial amount

r = percentage decrease

n = duration

From the given question,

[tex]A_0=500[/tex]

r = [tex]\frac{1}{4}=\frac{25}{100}[/tex]

Therefore, equation for the decrease in number of candies will be.

[tex]A=500(1-0.25)^n[/tex]

[tex]A=500(0.75)^n[/tex]

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