Answer:
pH = 9.56
Explanation:
Let's assume we have 1 liter of the solution. Then we would have 3.11 mg of Ba(OH)₂.
We convert 3.11 mg of Ba(OH)₂ into moles, using its molar mass:
- 3.11 mg / 1000 = 0.00311 g
- 0.00311 g ÷ 171.34 g/mol = 1.82x10⁻⁵ mol Ba(OH)₂
There are two OH⁻ moles per Ba(OH)₂ mol. Meaning there's (2*1.82x10⁻⁵) 3.63x10⁻⁵ moles of OH⁻.
As the volume is 1 L, the molar concentration of OH⁻, [OH⁻] is 3.63x10⁻⁵ M.
With the above information in mind we calculate the pOH of the solution:
Finally we calculate the pH:
