Question

3. What was the temperature in
Celsius change if 75 grams of
a substance with a specific
heat of 4.25 absorbed 2450 J
of heat?

Answer 1

q = mcΔT

m = 75 g
c = 4.25 J/gram°C
q = 2450 J

q/mc = ΔT

2450/(75 • 4.25) = 7.7°C

The temperature increased by 7.7°C.