Question

If the length of a rectangle is decreased by 6 cm and the width is increased by 3 cm, the result will be a square, the area of which will be 27 cm^2 smaller than the area of the rectangle. Find the area of the rectangle. PLZZZZZZ HELP WILL MAKE BRAINLIEST!!!

Answer 1

Answer:

Step-by-step explanation:

L-6=W+3

L=W+9

LW-(L-6)(W+3)=27, using L from above makes this

W(W+9)-(W+9-6)(W+3)=27

W^2+9W-(W+3)(W+3)=27

W^2+9W-W^2-6W-9=27

3W-9=27

3W=36

W=12, since L=W+9

L=12+9=21

A=LW

A=21(12)

A=252 cm^2

Answer 2

The area of the rectangle is 252 cm^2.

Calculation of the area of the rectangle:

Since

If the length of a rectangle is decreased by 6 cm and the width is increased by 3 cm.

So it can be like

L-6=W+3

L=W+9

Now

LW-(L-6)(W+3)=27

So,

W(W+9)-(W+9-6)(W+3)=27

W^2+9W-(W+3)(W+3)=27

W^2+9W-W^2-6W-9=27

3W-9=27

3W=36

Also,

W=12, since L=W+9

L=12+9=21

So,

A=LW

A=21(12)

A=252 cm^2

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