Question

help please I will give brainliest​

Answer 1

Answer:

choice 3) ∠BFG = (arc GB + arc CD)/2

Step-by-step explanation:

Angle formed by two chords theorem

Answer 2

Answer:

$m\angle BFG =\frac{ (m\widehat {GB} + m\widehat {CD})}{2}$

Step-by-step explanation:

By the property of intersecting chords, we have:

$m\angle BFG =\frac{1}{2} (m\widehat {GB} + m\widehat {CD} )$

$m\angle BFG =\frac{ m\widehat {GB} + m\widehat {CD}}{2}$