9514 1404 393
Answer:
no real solutions; k = ±i(2/3)√15
Step-by-step explanation:
If k is one of the roots, then substituting it for x will satisfy the equation:
k -4k -20/k = 0
Multiplying by k gives ...
-3k^2 -20 = 0
k^2 = -20/3 = -6 2/3
There are no real values of k such that this is true.
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If we allow k to be imaginary, then ...
k = ±i√(20/3) = ±i(2/3)√15
Possible imaginary values of k are ±(2/3)√15.
