Please help! Question is in picture. I will give Brainliest!!
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Answer:
(d) They may be combines
Step-by-step explanation:
Given
[tex]6\sqrt{32} - 12\sqrt{72}[/tex]
Required
Which option is true
Express 32 as 16 * 2 and 72 as 36 * 2
[tex]6\sqrt{32} - 12\sqrt{72} = 6\sqrt{16 * 2} - 12\sqrt{36 * 2}[/tex]
Split
[tex]6\sqrt{32} - 12\sqrt{72} = 6\sqrt{16} * \sqrt{2} - 12\sqrt{36} * \sqrt{2}[/tex]
This gives:
[tex]6\sqrt{32} - 12\sqrt{72} = 6*4 * \sqrt{2} - 12*6 * \sqrt{2}[/tex]
[tex]6\sqrt{32} - 12\sqrt{72} = 24 * \sqrt{2} - 72 * \sqrt{2}[/tex]
[tex]6\sqrt{32} - 12\sqrt{72} = 24 \sqrt{2} - 72 \sqrt{2}[/tex]
Since both term have the same radicand, then:
[tex]6\sqrt{32} - 12\sqrt{72} =( 24 - 72 )\sqrt{2}[/tex]
[tex]6\sqrt{32} - 12\sqrt{72} =-48\sqrt{2}[/tex]
Option (d) is correct