Respuesta :
Answer:
0.7769 = 77.69% probability that the owner will experience at least one Category III hurricane during the mortgage period
Step-by-step explanation:
We have only the mean, so we use the Poisson distribution to solve this question.
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:
[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]
In which
x is the number of sucesses
e = 2.71828 is the Euler number
[tex]\mu[/tex] is the mean in the given interval.
It uses the estimate that the probability of a named Category III hurricane or higher striking that particular region of the coast in any one year is 0.05.
This means that [tex]\mu = 0.05n[/tex], in which n is the number of yeas.
If a homeowner takes a 30-year mortgage on a recently purchased property, what is the likelihood that the owner will experience at least one Category III hurricane during the mortgage period
30 years means that [tex]\mu = 0.05*30 = 1.5[/tex].
This probability is:
[tex]P(X \geq 1) = 1 - P(X = 0)[/tex]
In which
[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]
[tex]P(X = 0) = \frac{e^{-1.5}*(1.5)^{0}}{(0)!} = 0.2231[/tex]
[tex]P(X \geq 1) = 1 - P(X = 0) = 1 - 0.2231 = 0.7769[/tex]
0.7769 = 77.69% probability that the owner will experience at least one Category III hurricane during the mortgage period
Let X become a variable refer to the number of Category ll hurricanes that occurred during the mortgage period. As per the information given, the variable x has a random variable.
- The mortgage duration is specified as n = 30, and the likelihood of a category ll hurricane in either given year is given as p=0.05.
For point a:
- The chances of seeing as least one Category lll hurricane are as follows:
[tex]\to P(X > 1) = 1 - P(X = 0)\\\\ \to P(X > 1) = 1^{-30} C_o (0.05)^0 (1 -0.05)^{30}\\\\ \to P(X > 1) = 0.7854[/tex]
For point b:
- The chances to see at least two category III hurricanes are as follows:
[tex]\to P(X > 2) = 1 - P(X =0) - P(X = 1)\\\\ \to P(X > 2) = 1 ^{-30} C_0(0.05)^0 (1 -0.05)^{30 -30} C_1 (0.05)^1+(1 - 0.05)^{29}\\\\ \to P(X > 2) = 0.4465[/tex]
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brainly.com/question/11667993