ramirez2435 ramirez2435

18-03-2021
Mathematics

contestada

Plz help for exam!!!
Solve for x and y.

Plz help for exam Solve for x and y class=

Respuesta :

bheam12 bheam12

18-03-2021

Answer:

A x-198,y-99[tex]\sqrt{3}[/tex]

Step-by-step explanation:

since sin p/h you can say

perpendicular is 99

and hypotenuse is x

sin 30=99/x

x=198

and cos is b/h

base is y

and hypotenuse is x

cos 30=y/198

y-99[tex]\sqrt{3}[/tex]

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