Plz help for exam!!!
Solve for x and y.

Answer:
A x-198,y-99[tex]\sqrt{3}[/tex]
Step-by-step explanation:
since sin p/h you can say
perpendicular is 99
and hypotenuse is x
sin 30=99/x
x=198
and cos is b/h
base is y
and hypotenuse is x
cos 30=y/198
y-99[tex]\sqrt{3}[/tex]