Question

How do u solve ax+b>cd

Answer 1

ax+b>cd
     -b   -b
-------------
ax>(cd)-b
/a      /a
-------------
x=(cd)-b/a        
                            
now lets use some numbers
a>4
b>2
c>6
d>1/2

4x+2>6(1/2)
    -2     -2
 ---------------
 4x>3-2
 4x>1
 /4    /4
--------------
 x>1/4
 
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Answer 2

The required solution is $x>\dfrac{cd-b}{a}$.  

Given:

The given inequality is $ax+b>cd$.

To find:

The solution to the given inequality.

Explanation:

We have,

$ax+b>cd$

Subtract $b$ from both sides.

$ax+b-b>cd-b$

$ax>cd-b$

Divide both sides by $a$.

$\dfrac{ax}{a}>\dfrac{cd-b}{a}$

$x>\dfrac{cd-b}{a}$

Therefore, the required solution is $x>\dfrac{cd-b}{a}$.

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