Question

Vector A⃗ has a magnitude of 3.00 and is directed parallel to the negative y-axis and vector B⃗ has a magnitude of 3.00 and is directed parallel to the positive y-axis. Determine the magnitude and direction angle (as measured counterclockwise from the positive x-axis) of vector C⃗ , if C⃗ =A⃗ −B⃗ .

C = 6.00; θ = 270˚
C = 3.00; θ = 270˚
C = 6.00; θ = 90˚
C = 3.00; θ = 90˚

Answer 1

The correct answer between all the choices given is the first choice, which is "C = 6.00; θ = 270˚". I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

Answer 2

Answer

C = 6.00; θ = 270˚

Explanation

A vector is described by giving both its magnitude and direction.

A = 3.00; 270°

B = -3.00; 90°

C = A - B. From this expression, it can be seen that we have already reversed the direction of B. So vector C is in the direction of A.

C = A - B

C = 3.00 - (-3.00)

= 6.00