Answer:
[tex]\Large \boxed{\sf -6000 \ J}[/tex]
Explanation:
Use formula
[tex]\displaystyle \sf Heat \ (J)=mass \ (kg) \times specific \ heat \ capacity \ (Jkg^{-1}\°C^{-1}) \times change \ in \ temperature \ (\°C)[/tex]
Specific heat capacity of ice is 2,000 J/(kg °C)
Substitute the values in formula and evaluate
[tex]\displaystyle \sf Heat \ (J)=0.05 \ kg \times 2000 \ Jkg^{-1}\°C^{-1} \times (-100\°C-(-40 \°C))[/tex]
[tex]Q=0.05 \times 2000 \times (-100-(-40)) =-6000[/tex]