Answer:
Option A
Step-by-step explanation:
Number of components assembled by the new employee per day,
N(t) = [tex]\frac{50t}{t+4}[/tex]
Number of components assembled by the experienced employee per day,
E(t) = [tex]\frac{70t}{t+3}[/tex]
Difference in number of components assembled per day by experienced ane new employee
D(t)= E(t) - N(t)
D(t) = [tex]\frac{70t}{t+3}-\frac{50t}{t+4}[/tex]
= [tex]\frac{70t(t+4)-50t(t+3)}{(t+3)(t+4)}[/tex]
= [tex]\frac{70t^2+280t-50t^2-150t}{(t+3)(t+4)}[/tex]
= [tex]\frac{20t^2+130t}{(t+3)(t+4)}[/tex]
= [tex]\frac{10t(2t+13)}{(t+4)(t+3)}[/tex]
Therefore, Option A will be the answer.
