Answer:
[tex]H_o:\mu = 26[/tex]
[tex]H_a:\mu < 26[/tex]
Step-by-step explanation:
Given
Average score is less than 26
Required
Determine the null and alternate hypothesis
Since the average is said to be less than 26; that represents the alternate hypothesis.
The null hypothesis will be:
[tex]Average = 26[/tex]
So, we have:
[tex]H_o:\mu = 26[/tex]
And the alternate hypothesis
[tex]H_a:\mu < 26[/tex]