Question

A community swimming pool is made up of four semicircles and a square. Find the perimeter of the swimming pool. Round your answer to the nearest tenth.


i'll give brainliest and i forgot to add the picture on my last one- so yea :)

Answer 1

Answer:

with the square inside: 708 ft

without the square: 628 ft

Step-by-step explanation:

perimeter of a semicirlce = $\frac{1}{2}$ (π$r^{2}$)

perimeter of a square = 4a

Perimeter of square: 4a

substitute 20 for a

⇒ 4a

⇒ 4 x 20

⇒ 80 ft

Perimeter of semicircle: $\frac{1}{2}$ (π$r^{2}$)

r = half of 20 which is 10

⇒ $\frac{1}{2}$ (π$r^{2}$)

⇒ $\frac{1}{2}$ (3.14 x $10^{2}$)

⇒ $\frac{1}{2}$ (3.14 x 100)

⇒ $\frac{1}{2}$ x 314

⇒ 157 ft

Since there are 4 semicirlces, just take 157 ft and multiply it by 4

⇒ 157 x 4

⇒ 628 ft

take 628 ft and add 80 ft:

⇒ 628 + 80

⇒708 ft