Question

In triangle PQR, angle P and R are complementary angles where cos P =(0.3) what is the measure in degrees of angle R round to the nearest tenth

Answer 1

Answer:

$R = 17.5$

Step-by-step explanation:

Given

P and R are complementary

$Cos\ P =0.3$

Required

Find the measure of R

$Cos\ P =0.3$

Take arccos of both sides

$P = cos^{-1}(0.3)$

$P = 72.5$

Since P and R are complementary, then:

$P + R = 90$

Make R the subject

$R = 90 - P$

Substitute values for P

$R = 90 - 72.5$

$R = 17.5$