The volume of 5 M NaOH needed is 20 mL
From the question given above, the following data were obtained:
Molarity of stock solution (M₁) = 5 M
Volume of diluted solution (V₂) = 100 mL
Molarity of diluted solution (M₂) = 1 M
The volume of the stock solution needed can be obtained as follow:
5 × V₁ = 1 × 100
5 × V₁ = 100
Divide both side by 5
V₁ = 100 / 5
Therefore, 20 mL of 5 M NaOH is needed.
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