Answer:
(a) See attachment
(b) Mara's rectangle
Step-by-step explanation:
Given
Mara
[tex]Area =15cm^2[/tex]
Ashton
[tex]Area =9cm^2[/tex]
Solving (a): Draw the rectangles
First, we need to calculate the possible dimension of both rectangles.
Area is calculated as:
[tex]Area = Length * Width[/tex]
For Mara
[tex]15 = Length * Width[/tex]
Possible values of length and width are:
[tex]Length = 5cm[/tex]
[tex]Width = 3cm[/tex]
This is so because:
[tex]5cm * 3cm = 15cm^2[/tex]
For Ashton
[tex]9 = Length * Width[/tex]
Possible values of length and width are:
[tex]Length = 4.5cm[/tex]
[tex]Width = 2cm[/tex]
This is so because:
[tex]4.5cm * 2cm = 9cm^2[/tex]
See attachment for diagram
Solving (b): Rectangle with bigger area
Mara's rectangle has a bigger area because [tex]15cm^2 > 9cm^2[/tex]