Question

3) 3 A force of -4.4x10^33 N exists between a positive charge of 8.0x10^-4 C and a
negative charge -3.0x10^-4 C. What is the distance that separates the charges?

Answer 1

Answer:

$r=7\times 10^{-16}\ m$

Explanation:

The force between charges, $F=-4.4\times 10^{33}\ N$

Positive charge, $q_1=8\times 10^{-4}\ C$

Negative charge, $q_2=-3\times 10^{-4}\ C$

We need to find the distance between charges. The force of attraction between charges is given by :

$F=\dfrac{kq_1q_2}{r^2}$

Where

r is the distance between charges

$r=\sqrt{\dfrac{kq_1q_2}{F}} \\\\r=\sqrt{\dfrac{9\times 10^9\times 8\times 10^{-4}\times 3\times 10^{-4}}{4.4\times 10^{33}}} \\\\r=7\times 10^{-16}\ m$

So, the distance between charges is $7\times 10^{-16}\ m$.