17-03-2021
Chemistry

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How many grams of hydrogen iodide are needed when 0.687 moles of hydrogen formed?
_Mn + _HI -> _MnI3 + _H₂

How many grams of hydrogen iodide are needed when 0687 moles of hydrogen formed Mn HI gt MnI3 H class=

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ganjilaya2019 ganjilaya2019

17-03-2021

[tex]2mn + \: 6hi \: - > 2mni3 \: + 3h2 \\ xg \: hi \: = 0.687mol \: h2 \times \frac{6mol \: hi}{3mol \: h2} \times \frac{127 \: g \: hi}{1mol \: hi} = 174.5 \: g \: hi[/tex]

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