Question

What is the correct set of image points for trapezoid W'X'Y'Z'?

1. W(4, -2), X’ (3, -4), Y’ (1, -4), Z (0, -2)
2. W (4,2), X"(3, 4), Y (1, 4), Z'(0, 2)
3. W(-2,-4), X (-4, -3), Y'(-4, -1), Z (-2, 0)
4. W (2, 4), X'(4, 3), Y (4, 1), Z' (2, 0)

Answer 1

Given:

The figure of a trapezoid.

To find:

The image points of the given figure after rotation of 180 degrees.

Solution:

From the given figure, it is clear that the vertices of the trapezoid are W(-4,2), X(-3,4), Y(-1,4), Z(0,2).

If a figure is rotated 180 degrees about the origin, then

$(x,y)\to (-x,-y)$

Using this rule, we get

$W(-4,2)\to W'(4,-2)$

$X(-3,4)\to X'(3,-4)$

$Y(-1,4)\to Y'(1,-4)$

$Z(0,2)\to Z'(0,-2)$

Therefore, the image points are W'(4,-2), X'(3, -4), Y'(1, -4), Z'(0, -2). So, the correct option is 1.