Answer:
[tex]\frac{1}{4k^3}[/tex]
Step-by-step explanation:
It's already in a form that only ha positive exponents. Just to state it though you could rewrite it as [tex]k*(4k^{4})^{-1}[/tex] or [tex]k*4^{-1}*k^{-4}[/tex] The question asks for positive exponents though so yu don't need to do that.
You also need to know [tex]\frac{x^a}{x^b}=x^{a-b}[/tex] so in this case [tex]\frac{k}{k^4}=\frac{k^1}{k^4} =k^{1-4}=k^{-3}=\frac{1}{k^3}[/tex]
so [tex]\frac{k}{4k^4}=\frac{1}{4}*\frac{k}{k^4}=\frac{1}{4}*\frac{1}{k^3}=\frac{1}{4k^3}[/tex]
