Answer:
( 1 , − 1 ) lies on y = 2 x −3.
Step-by-step explanation:
To check whether a point lies on the line, substitute either x or y
into its corresponding equation. If you get the other coordinate correctly from the equation, the point lies on that line.
Let's substitute x = 1 in y = 2 x − 3 ⇒ y = 2 × 1 − 3 = 2 − 3 ⇒ y = − 1
This corresponds to the y-coordinate in (1, -1). Thus the point (1, -1) lies on the given line.
Substitute y = 0 in the equation. 0 = 2 x − 3 implies3 = 2x ⇒ 3 = 2 x ⇒ x 3 = 2
For (-3, 0) to lie on the line, putting y = 0 should have given us x = − 3
. Since it didn't, the point does not lie on the line.
Similarly, (5,4) does not lie on the line. Try plugging in one of the values to see it.
graph{y = 2x -3 [-10, 10, -5, 5]}
