Question

LASTIC OF POTENTIAL ENERGY
stretched or compressed spring, elastic string or rubber, possess potential
nergy because they are potentially able to do work. This potential to do work
Fises from the fact that work is done in stretching or compressing the elastic
aterial. This ability of the stretched or compressed elastic material to do work
called elastic potential energy.
astic potential (w) = 12 fe=1/2 ke?
f=ke
cample
1) A spiral spring is compresses by 0.02m. calculate the energy store in the
spring, if the force constant is 400Nm.
Solution​

Answer 1

Answer:

E = 0.08 J

Explanation:

Given that,

The elastic potential energy of the spring is given by :

$E=\dfrac{1}{2}kx^2$

Where

k is spring constant

x is compression in the spring

We need to find the energy stored when force constant is 400 N-m and the compression is 0.02 m.

$E=\dfrac{1}{2}\times 400\times (0.02)^2\\\\E=0.08\ J$

So, the required energy in the spring is equal to 0.08  J.